3x^2-27x=3

Solution for 3x^2-27x=3 equation:

3x^2-27x=3

We move all terms to the left:

3x^2-27x-(3)=0

a = 3; b = -27; c = -3;
Δ = b2-4ac
Δ = -272-4·3·(-3)
Δ = 765
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{765}=\sqrt{9*85}=\sqrt{9}*\sqrt{85}=3\sqrt{85}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-3\sqrt{85}}{2*3}=\frac{27-3\sqrt{85}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+3\sqrt{85}}{2*3}=\frac{27+3\sqrt{85}}{6}
$